(Using Alias|wavefront PowerAnimator, but Matches Maya or Rhino Readily )To deduce the radius R of this world we use the connection between it and the perimeter P of its equator two · pi · R = P, in which the pi amount is roughly 3.141592. Because of the design of hexagons within the ball surface, it is possible to understand that the perimeter is equivalent to 15 occasions the span L. Consequently, if the ring has 360 levels, then every side L of this polygon corresponds to 360º / 15 = 24º ...